Current Transformer – Construction, Phasor and Errors
Current Transformer is an instrument transformer which steps down high value of current to a low value of current suitable for measurement devices. It is widely used in power system for measurement and protection purpose. We cannot think of power generation, transmission or distribution without using Current Transformer.
Construction of Current Transformer (CT):
There are two windings in a Current Transformer which are wound around a magnetic core. The winding having fewer numbers of turns is called Primary Winding and the winding having more turns is called Secondary winding. Primary winding is connected in series with the primary circuit i.e. the circuit in which current is to be measured. As the number of turns in primary winding is very less, therefore there is no any appreciable amount of voltage drop in this winding.
The secondary winding is connected with ammeter / wattmeter / protection relay coil. Since the impedance of metering / protection relay is very less, therefore we can say that a CT operates under short circuit condition.
Based on the construction, there are two types of current transformer. One is Live Tank CT and another one is Dead Tank CT. In both types, the core and windings are enclosed in a porcelain structure. This structure is filled with oil which provides necessary cooling to core as well as winding. Kraft paper provides insulation between core and winding. In the figure below, the three equipment in the front are live tank CT.
Symbol of Current Transformer:
A current transformer is shown as below.
In the above figure, CT is defined by its terminal P1 & P2 and ratio 100/1. Primary circuit in which CT is connected is shown carrying a current of 200 A. The secondary current of CT will be 200 / 100 = 2 A.
Parameters of Current Transformer:
A current transformer is defined by its current Turn Ratio, Accuracy Class, Accuracy Limit Factor and Instrument Safety Factor (ISF) etc. Accuracy class is determined by phase angle error and ratio error. In this post we will be discussing the basics. Before going into further discussion, it is better to understand some of the basic but important parameters. Ther are as follows:
- Turn Ratio is defined as the ratio of number of secondary winding turns to number of primary winding turns. It is often denoted by n and given as
n = Number of secondary winding turns / Number of primary winding turns
- Transformation Ratio is defined as the ratio of primary winding current to secondary winding current. It is denoted by R and given as
R = primary winding current / Secondary winding current
You might think that n & R should be equal. Yes, correct but this is the ideal case but there is nothing ideal. There are always some losses associated in a CT and hence Turn Ratio and Transformation Ratio are not equal.This gave rise to ratio error. We will discuss it latter in this post.
- Burden is defined as the volt ampere (VA) of connected load across the terminals for secondary winding of CT.
Equivalent Circuit of Current Transformer:
The equivalent circuit and phasor diagram of current transformer is shown in figure below.
Where
n = turn ratio
r_{s} = resistance of secondary winding
x_{s} = reactance of secondary winding
r_{e} = resistance of burden connected to secondary
x_{e} = reactance if burden connected to secondary
E_{p} = Induced emf in CT primary
E_{s} = Induced voltage in CT secondary
N_{p} = CT primary winding turns
N_{s} = CT secondary winding turns
I_{p} = CT primary winding current
I_{s} = CT secondary winding current
Ø = Flux in CT core
ɵ = Phase angle of CT
I_{0} = Excitation current of CT
I_{m} = Magnetizing current of CT
Phasor Diagram of Current Transformer:
Carefully observe that the equivalent circuit and phasor diagram are same as that of power transformer. The phasor diagram is drawn assuming that connected burden is of lagging power factor. As CT is connected in series with the primary circuit whose current is to be measured, this means that primary current I_{p} of CT is not dependent on secondary burden rather it is determined by the primary circuit current.
From the above phasor, we will calculate the Transformation Ratio and Phase angle of CT.
Transformation Ratio:
For finding transformation ratio we need to calculate primary current I_{p} as per definition and then divide it by secondary current I_{s}. Let us consider the part of phasor of our importance for calculating I_{p} as shown below.
From the above phasor, it can be easily observed that primary current I_{p} is phasor sum of nI_{s} and I_{0}. The angle between and is (90-α-δ). (How?)
This is because I_{0} and ac are parallel line and a third line oa is cutting this parallel line. Hence corresponding angles will be equal.
Therefore primary current Ip can be calculated using vector addition formula.
I_{p} = [(nI_{s})^{2}+(I_{0})^{2}+2nI_{s}I_{0}Cos(90-α-δ)]^{1/2}
= [(nI_{s})^{2}+(I_{0})^{2}+2nI_{s}I_{0}Sin(α+δ)]^{1/2}
Hence,
Transformation Ratio,
R = I_{p}/I_{s}
= [(nI_{s})^{2}+(I_{0})^{2}+2nI_{s}I_{0}Sin(α+δ)]^{1/2} / I_{s}
Since magnetizing current I_{0} is very very small when compared with primary current I_{p}, therefore for approximation we can proceed as below,
R = [(nI_{s})^{2}+(I_{0})^{2}+2nI_{s}I_{0}Sin(α+δ)]^{1/2} / I_{s}
= [(nI_{s})^{2}+(I_{0} Sin(α+δ))^{2}+2nI_{s}I_{0}Sin(α+δ)]^{1/2} / I_{s}
= [{nI_{s}+ I_{0} Sin(α+δ)}^{2}]^{1/2} / I_{s}
= [nI_{s}+ I_{0} Sin(α+δ)] / I_{s}
= n + (I_{0}/ I_{s})Sin(α+δ)
Thus.
Transformation Ratio R = n + (I_{0}/ I_{s})Sin(α+δ) |
Following points should be noted from the above expression:
- Transformation ratio is not equal to CT turn ratio.
- Transformation ratio depends on excitation current and excitation angle.
- For transformation ratio to be equal to turn ratio, α = δ =0. This means that there should not be any core loss in the current transformer and burden should be purely resistive.
Phase Angle of Current Transformer:
Phase angle of current transformer is the angle between the primary current I_{p} and secondary current I_{s} when reversed. In above phasor diagram, θ is the phase angle.
In the above phasor, consider right angled triangle obc
tanθ = bc/ob
= I_{0}Sin(90-α-δ) / (oa+ab)
= I_{0}Cos(α+δ) / [nI_{s}+I_{0}Sin(α+δ)]
Since θ is very small, hence tanθ will be approximately equal to θ. Therefore we can write,
Θ = I_{0}Cos(α+δ) / [nI_{s}+I_{0}Sin(α+δ)]
Also, I_{0} is very very small, therefore I_{0}Sin(α+δ)<<<<nI_{s}, neglecting I_{0}Sin(α+δ)
Θ = I_{0}Cos(α+δ) / nI_{s}
= [I_{0}CosαCosδ – I_{0}SinαSinδ] / nI_{s}
From phasor, I_{m} = I_{0}Cosα and I_{e} = I_{0}Sinα, hence
Θ = [I_{m}Cosδ – I_{e}Sinδ] / nI_{s} Radian
= (180/π) [I_{m}Cosδ – I_{e}Sinδ] / nI_{s} degree
Phase Angle Θ = (180/π) [I_{m}Cosδ – I_{e}Sinδ] / nI_{s} degree |
Ratio Error of Current Transformer:
Ratio Error is defined as the per unit deviation in transformation ratio from nominal ratio. It is expressed in percentage.
Percentage Ratio Error E
= (Nominal Ration – Transformation Ratio)x100 / Transformation Ratio
Since the burden of current transformer is usually resistive, therefore power factor of burden is almost unity. Hence δ=0,
R = n + (I_{0}Sinα / I_{s}) but I_{0}Sinα = I_{e}
= n + I_{e}/I_{s}
Therefore, percentage ratio error can be calculated easily.
Phase Angle Error of Current Transformer:
Ideally the angle between the primary current and secondary current should be 180 degree. But there is some deviation from 180 degree. This deviation is called phase angle error. As can be seen from phasor, this departure is by an angle θ. This means,
Phase difference between primary current and secondary current = θ
Since the burden of current transformer is usually resistive, therefore power factor of burden is almost unity. Hence δ=0. Therefore
Phase angle error θ = (180/π) I_{m} / nI_{s} degree
Precaution:
CT secondary should never be kept open. An open CT secondary causes a high voltage across the CT secondary terminals which may cause damage of equipment / personnel.
Sir kindly give a practical example of ratio error calculation
You want ratio error calculation. I will post on it soon.